c) The area of a rectangle is \( 70 \mathrm{~cm}^{2} \) and it is 7 m broad. \( \begin{array}{ll}\text { (i) Find its length } & \text { (ii) Find its perimeter }\end{array} \)

To find the length of the rectangle, we use the area formula: Area = Length × Breadth. Given that the area is \( 70 \, \text{cm}^2 \) and the breadth (width) is 7 m (which is 700 cm), we rearrange the formula to get Length = Area ÷ Breadth. So, Length = \( 70 \, \text{cm}^2 \div 700 \, \text{cm} = 0.1 \, \text{cm}\). Now for the perimeter: Perimeter = 2 × (Length + Breadth). With Length = \( 0.1 \, \text{cm} \) and Breadth = \( 700 \, \text{cm} \), the perimeter is \( 2 \times (0.1 + 700) = 2 \times 700.1 = 1400.2 \, \text{cm} \). So in summary, the length is \( 0.1 \, \text{cm} \) and the perimeter is \( 1400.2 \, \text{cm} \).