Chapier 1 Lesson 8: Adding and Subiracting 1. $$ 1 \frac{1}{4}-\frac{3}{4}= $$ 2ecompositions (4) $$ \frac{6}{4}-\frac{3}{4}=\frac{3}{4} $$ (3) $$ \frac{4}{4}-\frac{3}{4}=\frac{1}{4} $$ (-) $$ \frac{4}{8}-\frac{3}{4}=\frac{1}{4} $$ (D $$ \frac{5}{4}-\frac{3}{4}=\frac{2}{4}=\frac{1}{2} $$ 2. How many sevenths are there in 3 whole pizza?

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**Problem 1**

We start with the mixed number subtraction:

$$
1\frac{1}{4} - \frac{3}{4}
$$

1. Convert the mixed number $$1\frac{1}{4}$$ to an improper fraction:

$$
1\frac{1}{4} = \frac{4 \times 1 + 1}{4} = \frac{5}{4}
$$

2. Subtract the fractions, noting that they have a common denominator:

$$
\frac{5}{4} - \frac{3}{4} = \frac{5 - 3}{4} = \frac{2}{4}
$$

3. Simplify $$\frac{2}{4}$$:

$$
\frac{2}{4} = \frac{1}{2}
$$

So,

$$
1\frac{1}{4} - \frac{3}{4} = \frac{1}{2}
$$

---

**Problem 2**

Determine how many sevenths are in 3 whole pizzas. Each whole pizza can be thought of as $$ \frac{7}{7} $$. For 3 pizzas:

1. Express 3 pizzas in terms of sevenths:

$$
3 \text{ pizzas} = 3 \times \frac{7}{7} = \frac{21}{7}
$$

2. The fraction $$\frac{21}{7}$$ tells us that there are 21 pieces when each piece is $$\frac{1}{7}$$ of a pizza.

Thus, there are 21 sevenths in 3 whole pizzas.
**Problem 1** $$ 1\frac{1}{4} - \frac{3}{4} = \frac{1}{2} $$ **Problem 2** There are 21 sevenths in 3 whole pizzas.

Chapier 1
Lesson 8: Adding and Subiracting

2ecompositions
(4)
(3)
(-)
(D

How many sevenths are there in 3 whole pizza?

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Chapier 1 Lesson 8: Adding and Subiracting 2ecompositions (4) (3) (-) (D How many sevenths are there in 3 whole pizza?