Write the equation for a cosine function with amplitude \( 3 \pi \), period 1 , and phase shift \( =8 \).
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Bonus Knowledge
The equation for a cosine function can be represented as: \[ y = A \cos(B(x - C)) + D \] Here, \( A \) is the amplitude, \( B \) is related to the period, \( C \) is the phase shift, and \( D \) is the vertical shift (which we'll assume is zero for this equation). Given an amplitude of \( 3 \pi \), period of \( 1 \), and a phase shift of \( 8 \), we can substitute these values into the equation. The period \( P \) is related to \( B \) by the formula \( P = \frac{2\pi}{B} \). Since the period is \( 1 \), we have: \[ 1 = \frac{2 \pi}{B} \implies B = 2\pi \] Now, substituting the values: \[ y = 3\pi \cos(2\pi(x - 8)) \] This function will have the desired properties of amplitude \( 3\pi \), period \( 1 \), and a phase shift of \( 8 \) units to the right!
