39. $$ 25^{3 n-1} imes 125^{3-n} imes 5^{-6} \div 5^{3 n+1} $$

Question

39. $$ 25^{3 n-1} 	imes 125^{3-n} 	imes 5^{-6} \div 5^{3 n+1} $$

UpStudy AI · Accepted Answer

Calculate or simplify the expression $$ 25^{3n-1} 	imes 125^{3-n} 	imes 5^{-6} \div 5^{3n+1} $$.
Simplify the expression by following steps:
- step0: Solution:
  $$25^{3n-1}	imes 125^{3-n}	imes 5^{-6}\div 5^{3n+1}$$
- step1: Multiply by $$a^{-n}:$$
  $$25^{3n-1}	imes 125^{3-n}	imes 5^{-6}	imes 5^{-\left(3n+1ight)}$$
- step2: Calculate:
  $$25^{3n-1}	imes 125^{3-n}	imes 5^{-6}	imes 5^{-3n-1}$$
- step3: Transform the expression:
  $$5^{2\left(3n-1ight)}	imes 5^{3\left(3-night)}	imes 5^{-6}	imes 5^{-3n-1}$$
- step4: Multiply the terms:
  $$5^{2\left(3n-1ight)+3\left(3-night)-6-3n-1}$$
- step5: Calculate:
  $$5^{0}$$
- step6: Evaluate the power:
  $$1$$
เมื่อคำนวณ $$25^{3n-1} 	imes 125^{3-n} 	imes 5^{-6} \div 5^{3n+1}$$ จะได้ผลลัพธ์เป็น 1
ผลลัพธ์ของสมการ $$ 25^{3n-1} 	imes 125^{3-n} 	imes 5^{-6} \div 5^{3n+1} $$ คือ 1

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