Solve: $$ -7 x^{2}+10=185 $$ I'm not sure. $$ x=3,-3 $$ $$ x=5,-5 $$ $$ x=3 $$

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Solve the equation(The complex numbers system) by following steps:
- step0: Solve using square roots:
  $$-7x^{2}+10=185$$
- step1: Add or subtract both sides:
  $$-7x^{2}=175$$
- step2: Divide both sides:
  $$\frac{-7x^{2}}{-7}=\frac{175}{-7}$$
- step3: Divide the numbers:
  $$x^{2}=-25$$
- step4: Simplify the expression:
  $$x=\pm \sqrt{-25}$$
- step5: Simplify the expression:
  $$x=\pm 5i$$
- step6: Separate into possible cases:
  $$\begin{align}&x=5i\&x=-5i\end{align}$$
- step7: Rewrite:
  $$x_{1}=-5i,x_{2}=5i$$
- step8: Remove the complex number(s):
  $$\textrm{No real solution}$$
Let's solve the equation step by step:

1. Start with the equation:
   $$
   -7x^{2} + 10 = 185
   $$

2. Subtract 10 from both sides to isolate the term with $$x$$:
   $$
   -7x^{2} = 185 - 10
   $$
   $$
   -7x^{2} = 175
   $$

3. Divide both sides by -7 to solve for $$x^{2}$$:
   $$
   x^{2} = \frac{175}{-7}
   $$
   $$
   x^{2} = -25
   $$

4. Since $$x^{2} = -25$$, we see that there are no real solutions because the square of a real number cannot be negative.

Thus, the conclusion is that there are **no real solutions** for the equation $$ -7x^{2} + 10 = 185 $$.

The options you provided (like $$ x=3, -3 $$ or $$ x=5, -5 $$) are incorrect because the equation does not yield any real values for $$x$$.
There are no real solutions for the equation $$ -7x^{2} + 10 = 185 $$.

Solve: \( -7 x^{2}+10=185 \) I'm not sure. \( x=3,-3 \) \( x=5,-5 \) \( x=3 \)

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