rk 7 Part Il: Probability Using utations A warehouse employs 21 workers on first shift, 18 workers on second shift, and 14 workers on third shift. Eight workers are chosen at random to be inter \( 57.14 \%, 40 \) choosing exactly four third-shift workers. Points: 0 of 1

We start by noting that the warehouse has a total of \[ 21 + 18 + 14 = 53 \text{ workers.} \] We choose 8 workers at random. To have exactly four third‐shift workers among those eight, we must select: 1. Four workers from the 14 third‐shift workers. 2. The remaining four workers from the 39 non–third‐shift workers (i.e. first and second shifts combined, \(21+18=39\)). The number of ways to choose four third‐shift workers is given by \[ \binom{14}{4}. \] The number of ways to choose four workers from the other 39 is \[ \binom{39}{4}. \] Thus, the total number of favorable outcomes is \[ \binom{14}{4}\binom{39}{4}. \] The total number of ways to choose any 8 workers from 53 is \[ \binom{53}{8}. \] Therefore, the desired probability is \[ P = \frac{\binom{14}{4}\binom{39}{4}}{\binom{53}{8}}. \]