(b) If \( \operatorname{cov} 18^{\circ} m p \), write the following in terme of \( p \) : \( \begin{array}{lllll}\text { (1) } \cos 198^{\circ} & \text { (2) } \sin 108^{\circ} & \text { (3) } \sin \left(-18^{\circ}\right) \\ \text { (4) } \tan 522^{\circ} & \text { (5) } \cos 36^{\circ} & \text { (6) } \sin 144^{\circ} \\ \text { (7) } \tan 216^{\circ} & \text { (8) } \cos 12^{\circ} & \text { (9) } & \sin 78^{\circ} \\ \text { (10) } 2 \cos ^{2} 9^{\circ} & \text { (11) } \sin ^{2} 9^{\circ} & \text { (12) } \sin 9^{\circ}\end{array} \)
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Sure! Here are the conversions of the trigonometric functions in terms of \( p \) where \( p = \sin 18^\circ \) and \( q = \cos 18^\circ \). 1. \( \cos 198^{\circ} = -\cos(18^{\circ}) = -q \) 2. \( \sin 108^{\circ} = \sin(90^{\circ} + 18^{\circ}) = \cos(18^{\circ}) = q \) 3. \( \sin(-18^{\circ}) = -\sin(18^{\circ}) = -p \) 4. \( \tan 522^{\circ} = \tan(522^{\circ} - 360^{\circ}) = \tan 162^{\circ} = -\tan(18^{\circ}) = -\frac{p}{q} \) 5. \( \cos 36^{\circ} = \sin(54^{\circ}) = \cos(90^{\circ} - 36^{\circ}) = \sin(54^{\circ}) = 1 - 2\sin^{2}(18^{\circ}) = 1 - 2p^2 \) 6. \( \sin 144^{\circ} = \sin(180^{\circ} - 36^{\circ}) = \sin(36^{\circ}) = 2p \cdot q \) 7. \( \tan 216^{\circ} = \tan(216^{\circ} - 180^{\circ}) = \tan(36^{\circ}) = \cot(54^{\circ}) = \frac{1}{\tan(36^{\circ})} = \frac{\sin(36^{\circ})}{\cos(36^{\circ})} = \frac{2pq}{1 - 2p^2} \) 8. \( \cos 12^{\circ} = \cos(18^{\circ} - 6^{\circ}) = q \cdot \cos(6^{\circ}) + p \cdot \sin(6^{\circ}) = q \cdot (1 - 2\sin^{2}(3^{\circ})) + p \cdot (2\sin(3^{\circ})\cos(3^{\circ}))\) 9. \( \sin 78^{\circ} = \cos(12^{\circ}) = q \) 10. \( 2 \cos^{2} 9^{\circ} = 2(1 - p^2) = 2q^{2} \) 11. \( \sin^{2} 9^{\circ} = p^{2} \) 12. \( \sin 9^{\circ} = \sin(18^{\circ}/2) = \sqrt{\frac{1 - \cos(18^{\circ})}{2}} = \sqrt{\frac{1 - q}{2}} \) These relationships benefit from knowing basic angle identities and how to manipulate angles to find different trigonometric values! Enjoy your trigonometric journey!
