5. Given $$ \sin 34^{\circ}=p $$, find the value of $$ \sin 17^{\circ} \cos 17^{\circ} $$ in terms of $$ p $$

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We can use the double angle identity for sine, which states that $$ \sin(2\theta) = 2 \sin(\theta) \cos(\theta) $$. Here, we can set $$ \theta = 17^{\circ} $$, so $$ 2\theta = 34^{\circ} $$.
From the double angle identity, we have:
$$
\sin(34^{\circ}) = 2 \sin(17^{\circ}) \cos(17^{\circ})
$$
Thus, we can express $$ \sin(17^{\circ}) \cos(17^{\circ}) $$ as:
$$
\sin(17^{\circ}) \cos(17^{\circ}) = \frac{1}{2} \sin(34^{\circ})
$$
Since $$ \sin(34^{\circ}) = p $$, we can substitute this into the equation:
$$
\sin(17^{\circ}) \cos(17^{\circ}) = \frac{1}{2} p
$$
The value of $$ \sin 17^{\circ} \cos 17^{\circ} $$ in terms of $$ p $$ is $$ \frac{1}{2} p $$.

Given , find the value of in terms of

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