Verify if the two functions are inverses by showing that \( f(g(x))=x \) and \( g(f(x))=\boldsymbol{x} \). \[ \begin{array}{l}f(x)=8 x-8 g(x)=\frac{x}{8}-1 \\ \text { O Inverses } \\ \text { ONot Inverses } \\ >\text { Next Question }\end{array} \]

To verify if the functions are inverses, we can start by calculating \( f(g(x)) \): First, substitute \( g(x) \) into \( f(x) \): \[ f(g(x)) = f\left(\frac{x}{8}-1\right) = 8\left(\frac{x}{8}-1\right) - 8 = x - 8 - 8 = x - 16 \] This gives us \( f(g(x)) = x - 16 \), which is not equal to \( x \). Now, let's calculate \( g(f(x)) \): \[ g(f(x)) = g(8x - 8) = \frac{8x - 8}{8} - 1 = x - 1 - 1 = x - 2 \] This gives us \( g(f(x)) = x - 2 \), which is also not equal to \( x \). Since neither \( f(g(x)) = x \) nor \( g(f(x)) = x \), we can conclude that the two functions are not inverses of each other. Thus, the answer is: **Not Inverses**.