Suppose that the functions \( f \) and \( g \) are defined for all real numbers \( x \) as follows. \[ \begin{array}{l}f(x)=x^{3} \\ g(x)=3 x^{2} \\ (g \cdot f)(x)=\text { Write the expressions for }(g \cdot f)(x) \text { and }(g-f)(x) \text { and evaluate }(g+f)(2) \\ (g-f)(x)=\square\end{array} \] \( (g+f)(2)=\square \)
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Let's analyze the functions step by step. 1. To compute \( (g \cdot f)(x) \), we multiply \( g(x) \) and \( f(x) \): \[ (g \cdot f)(x) = g(x) \cdot f(x) = (3x^{2}) \cdot (x^{3}) = 3x^{5}. \] Therefore, \( (g \cdot f)(x) = 3x^{5} \). 2. Next, we find \( (g - f)(x) \): \[ (g - f)(x) = g(x) - f(x) = 3x^{2} - x^{3} = -x^{3} + 3x^{2}. \] So, \( (g - f)(x) = 3x^{2} - x^{3} \). 3. Lastly, we evaluate \( (g + f)(2) \): \[ (g + f)(x) = g(x) + f(x) = 3x^{2} + x^{3}. \] Now plug in \( x = 2 \): \[ (g + f)(2) = 3(2^{2}) + (2^{3}) = 3(4) + 8 = 12 + 8 = 20. \] For the results: \[ (g - f)(x) = 3x^{2} - x^{3} \quad \text{and} \quad (g + f)(2) = 20. \]
