Question 2 (1 point) Translate from Logarithmic Form to exponential form: $$ \log _{2}(8)=3 $$ $$ 2^{3}=8 $$ $$ 3^{2}=8 $$ $$ 8^{2}=3 $$ $$ 2^{8}=3 $$

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To translate the logarithmic form $$ \log_{2}(8) = 3 $$ into exponential form, we follow the definition of logarithms. The logarithmic equation states that the base (in this case, 2) raised to the power of the logarithm (which is 3) equals the argument of the logarithm (which is 8).

This can be expressed as:

$$
b^y = x \quad \text{where} \quad \log_b(x) = y
$$

In our case:
- $$ b = 2 $$
- $$ y = 3 $$
- $$ x = 8 $$

Thus, we can write:

$$
2^3 = 8
$$

Now, let's evaluate the other options to confirm which one is correct:

1. $$ 2^{3} = 8 $$ (This is correct)
2. $$ 3^{2} = 8 $$ (This is incorrect)
3. $$ 8^{2} = 3 $$ (This is incorrect)
4. $$ 2^{8} = 3 $$ (This is incorrect)

The correct translation from logarithmic form to exponential form is:

$$
\boxed{2^{3} = 8}
$$
$$ 2^{3} = 8 $$

Question 2 (1 point) Translate from Logarithmic Form to exponential form: \( \log _{2}(8)=3 \) \( 2^{3}=8 \) \( 3^{2}=8 \) \( 8^{2}=3 \) \( 2^{8}=3 \)

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