Write the prime factorization of 320 . Use exponents when appropriate and order the from least to greatest (for example, $$ 2^{2} \cdot 3 \cdot 5 $$ ).

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Let's determine the prime factorization of $$320$$ step by step.

1. **Divide by 2 as long as possible:**  
   Since $$320$$ is even, we keep dividing by $$2$$:

$$
   \begin{aligned}
   320 \div 2 &= 160, \
   160 \div 2 &= 80, \
   80 \div 2 &= 40, \
   40 \div 2 &= 20, \
   20 \div 2 &= 10, \
   10 \div 2 &= 5.
   \end{aligned}
   $$

2. **Count the factors of 2:**  
   We divided by $$2$$ a total of 6 times. This gives us $$2^6$$.

3. **Identify the remaining factor:**  
   After dividing by $$2$$ six times, we are left with $$5$$, which is a prime number.

4. **Write the final prime factorization:**  
   Combining the factors we found, the prime factorization of $$320$$ is:

$$
   320 = 2^6 \cdot 5.
   $$

Thus, the prime factorization of $$320$$ in order from least to greatest is:

$$
\boxed{2^6 \cdot 5}
$$
The prime factorization of 320 is $$2^6 \cdot 5$$.

Write the prime factorization of 320 . Use exponents when appropriate and order the from least to greatest (for example, \( 2^{2} \cdot 3 \cdot 5 \) ).

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