Question 5 (1 point) Solve. \[ 2 x^{2}-39=33 \] a \( \pm 3 \) b no real number solution c \( \pm 6 \) d \( d \geq \sqrt{6} \)
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To solve the equation \(2x^{2}-39=33\), start by simplifying it. Add 39 to both sides to get: \[2x^{2} = 72\]. Next, divide both sides by 2 to isolate \(x^{2}\): \[x^{2} = 36\]. Now take the square root of both sides, giving you \(x = \pm 6\). So the correct answer is \(c \pm 6\). As for common mistakes, many make the error of forgetting to isolate the squared variable before taking the square root. Ensure you've simplified correctly and double-check your steps to avoid miscalculations!
