A project needs five filler panels of drywall, each of which must be \( 9 \frac{1}{2} \) inches wide. The drywall mechanic determines that the total width of the drywall needed to cut out the five pieces is \( \frac{95}{2} \) inches. Change this value to a mixed number. The five filler panels would need to be cut from a piece of drywall that is at least \( \square \) inches wide.

To convert \( \frac{95}{2} \) inches to a mixed number, first, divide 95 by 2. This gives you 47 with a remainder of 1, so \( \frac{95}{2} \) can be written as \( 47 \frac{1}{2} \) inches. Thus, the total width of the drywall needed is \( 47 \frac{1}{2} \) inches. When cutting out the five filler panels, you want to ensure that you have enough width for the panels plus some extra for adjustments. Therefore, you would need to source a piece of drywall that has at least \( 47 \frac{1}{2} \) inches in width to complete your project without any hassles. Happy drywalling!