Find the function value, if possible. (If an answer is undefined, enter UNDEFINED.) $$ f(x)=|x|+4 $$ (a) $$ f(6) $$ (b) $$ \quad(-6) $$ (c) $$ f\left(x^{2}\right) $$ (b)

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**(a)**  
To evaluate $$ f(6) $$, substitute $$ x = 6 $$ into the function:  
$$
f(6) = |6| + 4
$$  
Since $$|6| = 6$$, we have:  
$$
f(6) = 6 + 4 = 10
$$

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**(b)**  
It appears that the value $$-6$$ is provided. Interpreting this as evaluating $$ f(-6) $$, substitute $$ x = -6 $$ into the function:  
$$
f(-6) = |-6| + 4
$$  
Since $$|-6| = 6$$, we have:  
$$
f(-6) = 6 + 4 = 10
$$

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**(c)**  
To evaluate $$ f\left(x^2\right) $$, substitute $$ x = x^2 $$ into the function:  
$$
f\left(x^2\right) = \left|x^2\right| + 4
$$  
Since $$ x^2 $$ is nonnegative for all real $$ x $$, $$\left|x^2\right| = x^2$$. Therefore,  
$$
f\left(x^2\right) = x^2 + 4
$$

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**(b)**  
Assuming the repeat of $$(b)$$ is meant to evaluate $$ f(b) $$ for a variable $$ b $$, substitute $$ x = b $$ into the function:  
$$
f(b) = |b| + 4
$$  
This is the most simplified form for a general $$ b $$.

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Thus, the function evaluations are:  
- $$ f(6) = 10 $$  
- $$ f(-6) = 10 $$  
- $$ f\left(x^2\right) = x^2 + 4 $$  
- $$ f(b) = |b| + 4 $$
$$ f(6) = 10 $$, $$ f(-6) = 10 $$, $$ f(x^2) = x^2 + 4 $$, $$ f(b) = |b| + 4 $$.

Find the function value, if possible. (If an answer is undefined, enter UNDEFINED.) \[ f(x)=|x|+4 \] (a) \( f(6) \) (b) \( \quad(-6) \) (c) \( f\left(x^{2}\right) \) (b)

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