$$ 1 \leftarrow $$ If $$ f(x) $$ is defined as follows, find $$ (a) f(-3) $$, (b) $$ f(0) $$, and $$ (c) f(3) $$ $$ f(x)=\left\{\begin{array}{ll}x^{2} & ext { if } x0\end{array} ight. $$ (a) $$ f(-3)=\square $$ (Simplify your answer.) 1 of 3

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$$ 1 \leftarrow $$ If $$ f(x) $$ is defined as follows, find $$ (a) f(-3) $$, (b) $$ f(0) $$, and $$ (c) f(3) $$ $$ f(x)=\left\{\begin{array}{ll}x^{2} & 	ext { if } x<0 \ 2 & 	ext { if } x=0 \ 3 x+1 & 	ext { if } x>0\end{array}ight. $$ (a) $$ f(-3)=\square $$ (Simplify your answer.) 1 of 3

UpStudy AI · Accepted Answer

1. Since $$-3 < 0$$, we use the definition $$ f(x) = x^2 $$ for $$ x < 0 $$.

2. Substitute $$-3$$ into the formula:
   $$
   f(-3) = (-3)^2
   $$

3. Compute:
   $$
   (-3)^2 = 9
   $$

Thus, $$\boxed{9}$$ is the value of $$ f(-3) $$.
$$ f(-3) = 9 $$

\( 1 \leftarrow \) If \( f(x) \) is defined as follows, find \( (a) f(-3) \), (b) \( f(0) \), and \( (c) f(3) \) \( f(x)=\left\{\begin{array}{ll}x^{2} & \text { if } x<0 \\ 2 & \text { if } x=0 \\ 3 x+1 & \text { if } x>0\end{array}\right. \) (a) \( f(-3)=\square \) (Simplify your answer.) 1 of 3

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