The function \( f \) is defined as \( f(x)=6 x^{2}-7 x \). Find \( f(x-2) \). Write your answer without parentheses, and simplify it as much as pos \( f(x-2)=\square \)

To find \( f(x-2) \), we substitute \( x-2 \) into the original function \( f(x) = 6x^2 - 7x \). First, calculate \( f(x-2) \): \[ f(x-2) = 6(x-2)^2 - 7(x-2) \] Now, expand \( (x-2)^2 \): \[ (x-2)^2 = x^2 - 4x + 4 \] Substituting this back into \( f(x-2) \): \[ f(x-2) = 6(x^2 - 4x + 4) - 7(x - 2) \] Now distribute the \( 6 \) and \( -7 \): \[ = 6x^2 - 24x + 24 - 7x + 14 \] Combine like terms: \[ = 6x^2 - 31x + 38 \] Therefore, the simplified expression for \( f(x-2) \) is: \[ f(x-2) = 6x^2 - 31x + 38 \]