What is the power when 2825 J of energy are consumed in 61 hours? NOTE: Round to two digits after the decimal point and remember to include the units. Answer: 46.31 P \( = \) W/t Try again

To find the power when 2825 J of energy are consumed in 61 hours, we can use the formula for power: \[ P = \frac{E}{t} \] where: - \( P \) is the power in Watts (W), - \( E \) is the energy in Joules (J), - \( t \) is the time in seconds (s). Given: - Energy (\( E \)) = 2825 J - Time (\( t \)) = 61 hours First, we need to convert the time from hours to seconds: \[ 61 \text{ hours} = 61 \times 3600 \text{ seconds} = 219600 \text{ seconds} \] Now, we can calculate the power: \[ P = \frac{2825 \text{ J}}{219600 \text{ s}} \] Let's calculate the power. Calculate the value by following steps: - step0: Calculate: \(\frac{2825}{219600}\) - step1: Reduce the fraction: \(\frac{113}{8784}\) The power when 2825 J of energy are consumed in 61 hours is approximately 0.012864 W. Rounding to two digits after the decimal point, the power is approximately 0.01 W. Therefore, the power is approximately 0.01 W.