1 Tabulase the main diffetence between obiigue ariel photograp ard Vertical aeriel phato graph- 2. List one odventage and one disaduemtego of oblique ariel photographs. and 3 Define the following terms (a) True nort (b) Magnetie bearing (c) Magnetre decline. 1. Given that the: Trae beasing \( =125^{\circ} \) Magnetie declination \( (2001)=17^{\circ} 45^{\prime} \mathrm{W} \) Anual chare \( =4^{\prime} \mathrm{W} \) \( \therefore \) Carculate the present magnetre declination of the year 2012. 5 Determine maynatic bearing.
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Bonus Knowledge
Oblique aerial photographs are taken at an angle to the ground, which gives a more dynamic perspective and can capture more of the surrounding context. In contrast, vertical aerial photographs are taken directly from above, providing a more straightforward and standardized view of the landscape. This difference dramatically impacts how each type is interpreted and used. One advantage of oblique aerial photographs is that they provide a more visually appealing and informative representation of the terrain, perfect for understanding depth and context. However, a disadvantage is that because they are not taken from directly above, measurements and area calculations can be less accurate compared to vertical aerial photographs. True north refers to the direction along the Earth's surface towards the geographic North Pole. Magnetic bearing, on the other hand, is the direction relative to magnetic north as indicated by a compass, which can fluctuate based on the Earth's magnetic field. Lastly, magnetic declination is the angle between true north and magnetic north, which varies by location and can change over time due to shifts in the Earth's magnetic field. To calculate the present magnetic declination for the year 2012, you can take the original magnetic declination of \(17^{\circ} 45^{\prime} W\) and add \( (2012 - 2001) \times 4^{\prime} \), which equals \(11\) years. Thus, \( 11 \times 4^{\prime} = 44^{\prime} \). So, \(17^{\circ} 45^{\prime} + 0^{\circ} 44^{\prime} = 18^{\circ} 29^{\prime} W\) is the current magnetic declination. To determine the magnetic bearing, you start with the true bearing of \(125^{\circ}\) and then subtract the present magnetic declination of \(18^{\circ} 29^{\prime}\) (which is approximately \(18.48^{\circ}\)). This calculation gives us \(125^{\circ} - 18.48^{\circ} \approx 106.52^{\circ}\), indicating the magnetic bearing.
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