Dinitrogen oxide (or nitrous oxide), \( \mathrm{N}_{2} \mathrm{O} \), also known as laughing gas, is widoly used as an anesthetic in dontistry. How many grams are in 1.35 moles of dinitrogen axide? Express your answer using thiree significant figures.
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To find the mass of 1.35 moles of dinitrogen oxide (\( \mathrm{N}_{2} \mathrm{O} \)), you first need to calculate its molar mass. The molar mass of \( \mathrm{N}_{2} \mathrm{O} \) is approximately \( 2 \times 14.01 \, \text{g/mol} \) (for nitrogen) + \( 16.00 \, \text{g/mol} \) (for oxygen), which equals \( 44.02 \, \text{g/mol} \). Next, multiply the number of moles by the molar mass: \[ 1.35 \, \text{moles} \times 44.02 \, \text{g/mol} \approx 59.4 \, \text{grams} \] Thus, there are approximately \( 59.4 \, \text{grams} \) in \( 1.35 \, \text{moles} \) of dinitrogen oxide.
