Summarize all pertinent information obtained by applying the graphing strategy and sketch the graph of \( y=f(x) \). \( f(x)=\frac{x^{2}+9 x+18}{x^{2}+6 x+9} \) A. The domain is all real \( x \), except \( x=\square \). (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) B. The domain is all real \( x \). Find the \( x \)-intercepts of \( f(x) \). Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The \( x \)-intercept(s) is/are at \( x= \) (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) B. There are no \( x \)-intercepts.

First, to find the domain of the function \( f(x)=\frac{x^{2}+9x+18}{x^{2}+6x+9} \), we need to identify values that make the denominator zero. The denominator \( x^{2}+6x+9 \) can be factored as \( (x+3)^{2} \). Therefore, the function is undefined at \( x=-3 \). So, the domain is all real \( x \), except \( x=-3 \). Next, to find the \( x \)-intercepts, we set \( f(x)=0 \), which occurs when the numerator \( x^{2}+9x+18=0 \). Factoring, we find \( (x+3)(x+6)=0 \), giving us the intercepts at \( x=-3 \) and \( x=-6 \). However, since \( x=-3 \) makes the function undefined, the only \( x \)-intercept is at \( x=-6 \). A. The domain is all real \( x \), except \( x=-3 \). A. The \( x \)-intercept is at \( x=-6 \).