Pregunta
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Sketch a rational function subject to the given conditions. Horizontal asymptote: \( y=0 \) Vertical asymptote: \( x=-1 \) \( y \)-intercept: \( (0,1) \) No \( x \)-intercepts Range: \( (0, \infty) \)

Ask by Tran Chavez. in the United States
Mar 19,2025

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To sketch the rational function: 1. Draw a vertical asymptote at \( x=-1 \). 2. Draw a horizontal asymptote at \( y=0 \). 3. Plot the \( y \)-intercept at \( (0,1) \). 4. Ensure the function does not cross the x-axis. 5. The function should only take positive values, so its range is \( (0, \infty) \). This will give a rational function that meets all the specified conditions.

Solución

To sketch a rational function subject to the given conditions, we need to consider the following: 1. Horizontal asymptote: \( y=0 \) 2. Vertical asymptote: \( x=-1 \) 3. \( y \)-intercept: \( (0,1) \) 4. No \( x \)-intercepts 5. Range: \( (0, \infty) \) Given the horizontal asymptote \( y=0 \), the rational function will have a horizontal asymptote at \( y=0 \). The vertical asymptote at \( x=-1 \) indicates that the function will have a vertical asymptote at \( x=-1 \). The \( y \)-intercept at \( (0,1) \) means that the function will pass through the point \( (0,1) \). Since there are no \( x \)-intercepts, the function will not cross the x-axis. The range of the function is \( (0, \infty) \), which means the function will only take positive values. To sketch the rational function, we can start by plotting the vertical asymptote at \( x=-1 \) and the horizontal asymptote at \( y=0 \). Then, we can plot the \( y \)-intercept at \( (0,1) \) and ensure that the function does not cross the x-axis. Finally, we can sketch the function to satisfy the given conditions.

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The Deep Dive

To sketch a rational function that meets your criteria, consider the function \( f(x) = \frac{1}{x + 1} \). 1. The horizontal asymptote is \( y=0 \) since as \( x \) approaches infinity, \( f(x) \) approaches 0. 2. The vertical asymptote at \( x=-1 \) occurs because the function is undefined there, causing it to diverge to infinity or negative infinity on either side. 3. The \( y \)-intercept is \( (0, 1) \) since \( f(0) = 1 \). 4. The function has no \( x \)-intercepts; it never crosses the x-axis because the output is always positive for all values of \( x \) in the domain, and it only approaches the x-axis as \( x \) goes to positive or negative infinity. 5. The range is \( (0, \infty) \) as the function only produces positive outputs. Thus, our rational function is well-suited to your requirements! Grab your markers and start sketching this delightful curve!

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