2. A coin is tossed 3 times. Find the probability of getting (a) Exactly two heads (b) At least two tails
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When a coin is tossed 3 times, there are a total of 2^3 = 8 possible outcomes: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. For exactly two heads, the successful outcomes are HHT, HTH, and THH, which gives us 3 favorable outcomes. Therefore, the probability of getting exactly two heads is 3/8! For at least two tails, the successful outcomes are HTT, THT, TTH, and TTT. There are 4 favorable outcomes here, so the probability of getting at least two tails is 4/8, which simplifies to 1/2!
