\( 4 \quad A \quad \frac { 8 + 3 x } { 2 } = 13 + x \)

To solve the equation \( 4 \quad A \quad \frac { 8 + 3 x } { 2 } = 13 + x \), first simplify both sides. Start by multiplying both sides by 2 to eliminate the fraction: \[ 8 + 3x = 2(13 + x) \] Expanding the right side gives: \[ 8 + 3x = 26 + 2x \] Next, rearrange the terms to isolate \( x \): Subtract \( 2x \) from both sides: \[ 8 + 3x - 2x = 26 \] This simplifies to: \[ 8 + x = 26 \] Now, subtract 8 from both sides: \[ x = 26 - 8 \] So, we find: \[ x = 18 \] To verify, substitute \( x \) back into the original equation. Check both sides to ensure they equal. If they do, then you’ve successfully solved for \( x \)!