Pregunta
\#5.) SAT Question! In a right triangle, one angle measures \( x^{\circ} \), where \( \sin x^{\circ}=\frac{4}{5} \). What is \( \cos \left(90^{\circ}-x^{\circ}\right) ? \)
Ask by Bush Huang. in the United States
Mar 11,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
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\[
\cos \left(90^\circ - x^\circ\right) = \frac{4}{5}
\]
Solución
1. We are given that \( \sin x^\circ = \frac{4}{5} \).
2. Recall the cofunction identity for sine and cosine:
\[
\cos \left(90^\circ - x^\circ\right) = \sin x^\circ
\]
3. Substitute the given value into the identity:
\[
\cos \left(90^\circ - x^\circ\right) = \frac{4}{5}
\]
4. Therefore, the answer is:
\[
\boxed{\frac{4}{5}}
\]
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Simplifique esta solución Mind Expander
In a right triangle, the sine of an angle is equal to the cosine of its complementary angle. So, if \( \sin x^{\circ} = \frac{4}{5} \), it also holds that \( \cos(90^{\circ} - x^{\circ}) = \sin x^{\circ} \). Therefore, \( \cos(90^{\circ} - x^{\circ}) = \frac{4}{5} \). Additionally, using the Pythagorean theorem, we can find that if \( \sin x^{\circ} = \frac{4}{5} \), the opposite side is 4 and the hypotenuse is 5. The adjacent side can be calculated as \( \sqrt{5^2 - 4^2} = \sqrt{25 - 16} = \sqrt{9} = 3 \). Thus, \( \cos x^{\circ} = \frac{3}{5} \), reaffirming \( \cos(90^{\circ} - x^{\circ}) = \frac{4}{5} \).
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