1.1 Choose the best answer from those provided. Write only the question number and the correct letter: 1.1.1 In which of the following technical subjects do we use binary numbers the most: (1) A Civil Technology B Mechanical Technology C Electrical Technology D Engineering Graphics and Design 1.1.2 How do we pronounce the following binary number: 1011 (1) A One thousand and One B One Zero One One C Ten Eleven D One and Zero and One and One 1.1.3 What does the 2 represent in the following number: $$ 10101_{2} $$ (1) A Binary numbers B Decimal numbers C Octanal numbers D Hexadecimal numbers 1.2 State if the following statements are true or false: 1.2.1 Binary numbers consist only of TWO digits. 1.2.2 $$ 1+1=2 $$ in binary [5] QUESTION 2: BINARY NUMBERS 2.1 Convert the following decimal numbers to binary numbers: $$ 2.1 .1 \quad 5_{10} $$ $$ 2.1 .2 \quad 39_{10} $$ 2.2 Convert the following binary number to a decimal number: $$ 2.2 .1 \quad 1010_{2} $$ $$ 2.2 .2 \quad 110101_{2} $$

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UpStudy AI · Accepted Answer

**1.1.1** C  
**1.1.2** B  
**1.1.3** A

**1.2.1** True  
**1.2.2** False

**2.1.1**

To convert $$5_{10}$$ to binary:  
- Divide 5 by 2: quotient = 2, remainder = 1  
- Divide 2 by 2: quotient = 1, remainder = 0  
- Divide 1 by 2: quotient = 0, remainder = 1

Reading the remainders from bottom to top, we get:  
$$
5_{10} = 101_2
$$

**2.1.2**

To convert $$39_{10}$$ to binary:  
- $$39 \div 2 = 19$$ with remainder 1  
- $$19 \div 2 = 9$$ with remainder 1  
- $$9 \div 2 = 4$$ with remainder 1  
- $$4 \div 2 = 2$$ with remainder 0  
- $$2 \div 2 = 1$$ with remainder 0  
- $$1 \div 2 = 0$$ with remainder 1

Reading the remainders from bottom to top, we obtain:  
$$
39_{10} = 100111_2
$$

**2.2.1**

To convert $$1010_2$$ to decimal, use the positional values:  
$$
1 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 0 \times 2^0 = 8 + 0 + 2 + 0 = 10
$$
Thus,  
$$
1010_2 = 10_{10}
$$

**2.2.2**

To convert $$110101_2$$ to decimal, use the positional values:  
$$
1 \times 2^5 + 1 \times 2^4 + 0 \times 2^3 + 1 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 32 + 16 + 0 + 4 + 0 + 1 = 53
$$
Thus,  
$$
110101_2 = 53_{10}
$$
**1.1.1** C **1.1.2** B **1.1.3** A **1.2.1** True **1.2.2** False **2.1.1** $$5_{10} = 101_2$$ **2.1.2** $$39_{10} = 100111_2$$ **2.2.1** $$1010_2 = 10_{10}$$ **2.2.2** $$110101_2 = 53_{10}$$

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