Consider the following function. \[ f(x)=\left\{\begin{array}{rrr}5 x-2 & \text { if } & x=1 \\ x^{2}+1 & \text { if } & 15 x<11 \\ 7 & \text { if } & x \geq 11\end{array}\right. \] Which "piece(s)" should be used to find the \( y \)-intercept? Select all that apply. \( \square \) A. 7 \( \square \) B. \( x^{2}+1 \) \( \square \) C. \( 5 x-2 \)
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Beyond the Answer
To find the \( y \)-intercept of a function, you need to evaluate the function at \( x = 0 \). In this case, we substitute \( x = 0 \) into the relevant pieces of the function: 1. For \( x = 0 \): - The condition \( 15x < 11 \) holds true (since \( 0 < 11 \)), so we use the piece \( x^2 + 1 \), which gives \( 0^2 + 1 = 1 \). 2. The piece \( 5x - 2 \) is only applicable when \( x = 1 \), so it does not contribute to the \( y \)-intercept. 3. The piece \( 7 \) is referenced for \( x \geq 11 \), which does not apply at \( x = 0 \). So, only the piece \( B \) (\( x^2 + 1 \)) is used to find the \( y \)-intercept, giving a value of \( 1 \). Now, you can mark the following: \( \square \) A. 7 \( \checked \) B. \( x^{2}+1 \) \( \square \) C. \( 5 x-2 \)
