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To differentiate the function \( y = x^{9} e^{x} \), we need to apply the product rule, which states that if you have two functions \( u \) and \( v \), then the derivative \( (uv)' = u'v + uv' \). Here, let \( u = x^{9} \) and \( v = e^{x} \). First, we find the derivatives: - \( u' = 9x^{8} \) - \( v' = e^{x} \) Now, applying the product rule: \[ \frac{dy}{dx} = u'v + uv' = (9x^{8})(e^{x}) + (x^{9})(e^{x}) \] This simplifies to: \[ \frac{dy}{dx} = e^{x}(9x^{8} + x^{9}) \] Therefore, the final answer is: \[ \frac{dy}{dx} = e^{x}(9x^{8} + x^{9}) \]
