Question 11 (1 point) A committee is to have four members ( 2 women and 2 men). There are 4 men and 7 women available to serve on the committee. How many different committees can be formed?

To form a committee of 2 women from 7 and 2 men from 4, we can use the combination formula, which is \( C(n, r) = \frac{n!}{r!(n-r)!} \). Calculating for women: \( C(7, 2) = \frac{7!}{2!(7-2)!} = \frac{7 \times 6}{2 \times 1} = 21 \) Calculating for men: \( C(4, 2) = \frac{4!}{2!(4-2)!} = \frac{4 \times 3}{2 \times 1} = 6 \) Now, multiply the combinations for men and women: Total committees = \( 21 \times 6 = 126 \) So, 126 different committees can be formed!