Is $$ (-2,0) $$ a solution of $$ y=\frac{1}{2} x+1 $$ ? No Yes

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To determine if the point $$ (-2, 0) $$ is a solution of the equation $$ y = \frac{1}{2} x + 1 $$, we need to substitute $$ x = -2 $$ into the equation and see if it yields $$ y = 0 $$.

1. Substitute $$ x = -2 $$ into the equation:
   $$
   y = \frac{1}{2}(-2) + 1
   $$

2. Calculate the right-hand side:
   $$
   y = -1 + 1 = 0
   $$

Since substituting $$ x = -2 $$ gives us $$ y = 0 $$, the point $$ (-2, 0) $$ satisfies the equation.

Thus, the answer is **Yes**, $$ (-2, 0) $$ is a solution of $$ y = \frac{1}{2} x + 1 $$.
$$ (-2, 0) $$ is a solution of $$ y = \frac{1}{2} x + 1 $$.

Is \( (-2,0) \) a solution of \( y=\frac{1}{2} x+1 \) ? No Yes

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