Is \( (6,4) \) a solution of \( y=\frac{1}{2} x+1 \) ? Yes

To check if \( (6, 4) \) is a solution of the equation \( y=\frac{1}{2} x+1 \), we can substitute \( x = 6 \) into the equation. Calculating the right side: \[ y = \frac{1}{2}(6) + 1 = 3 + 1 = 4. \] Since the output \( y = 4 \) matches the given \( y \) value in the point \( (6, 4) \), then yes, it's indeed a solution! For fun, think of it like solving a puzzle—once you plug the numbers in, you see if everything clicks into place. If they match, hooray! You’ve solved it! Also, if you're getting into graphing, this exercise is a golden opportunity! If you sketch the line represented by the equation \( y=\frac{1}{2} x + 1 \), you’ll see that the point \( (6, 4) \) is not just a valid solution; it's a point that lies right on that line!