\begin{tabular}{|l||}\hline \multicolumn{1}{|c|}{ Water Pressure Application } \\ \hline In certain deep parts of oceans, the pressure of sea water, \( P \), in pounds per square foot, \\ at a depth of \( d \) feet below the surface, is given by the equation \( P=16+\frac{6 d}{11} \) \\ \hline \( \begin{array}{l}\text { If a scientific team uses special equipment to measures the pressure under water and } \\ \text { finds it to be } 574 \text { pounds per square foot, at what depth is the team making their } \\ \text { measurements? }\end{array} \) \\ If the pressure is 574 pounds per square feet, the team is measuring at \( \square \) \\ below the surface. \end{tabular}

To find the depth \( d \) at which the pressure reaches 574 pounds per square foot, we can set up the equation using the given formula: \[ 574 = 16 + \frac{6d}{11} \] First, subtract 16 from both sides: \[ 558 = \frac{6d}{11} \] Next, multiply both sides by 11 to eliminate the fraction: \[ 6138 = 6d \] Now, divide by 6 to solve for \( d \): \[ d = \frac{6138}{6} = 1023 \] So, the scientific team is measuring at a depth of 1023 feet below the surface. Sometimes, it's easy to misplace or mishandle the constants in equations; always double-check that each step adheres to the correct mathematical principles. If you confuse the pressure unit, you might end up with a measurement that makes no physical sense, like trying to find depth in miles instead of feet!