Graph the system below and write its solution. \[ \begin{array}{r}3 x+y=5 \\ y=-\frac{1}{3} x-3\end{array} \] Note that you can also answer "No solution" or "Infinitely many" solut

Solve the system of equations \( 3x+y=5;y=-\frac{1}{3}x-3 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}3x+y=5\\y=-\frac{1}{3}x-3\end{array}\right.\) - step1: Substitute the value of \(y:\) \(3x-\frac{1}{3}x-3=5\) - step2: Subtract the terms: \(\frac{8}{3}x-3=5\) - step3: Move the constant to the right side: \(\frac{8}{3}x=5+3\) - step4: Add the numbers: \(\frac{8}{3}x=8\) - step5: Multiply by the reciprocal: \(\frac{8}{3}x\times \frac{3}{8}=8\times \frac{3}{8}\) - step6: Multiply: \(x=3\) - step7: Substitute the value of \(x:\) \(y=-\frac{1}{3}\times 3-3\) - step8: Calculate: \(y=-4\) - step9: Calculate: \(\left\{ \begin{array}{l}x=3\\y=-4\end{array}\right.\) - step10: Check the solution: \(\left\{ \begin{array}{l}x=3\\y=-4\end{array}\right.\) - step11: Rewrite: \(\left(x,y\right) = \left(3,-4\right)\) The solution to the system of equations is \( (x, y) = (3, -4) \).