g. \( \frac{10}{2 x-1}=8 \)

To solve the equation \( \frac{10}{2x-1} = 8 \), start by multiplying both sides by \( 2x - 1 \) to eliminate the fraction: \[ 10 = 8(2x - 1). \] Expanding the right side gives: \[ 10 = 16x - 8. \] Next, add 8 to both sides: \[ 18 = 16x. \] Finally, divide both sides by 16 to find \( x \): \[ x = \frac{18}{16} = \frac{9}{8}. \] So, the solution is \( x = \frac{9}{8} \). To double-check, you can substitute \( \frac{9}{8} \) back into the original equation and confirm that both sides match up!