a) \( 8^{0}+(0,50)^{-3}-(0,25)^{-2}-3^{2} \)

Let's break down the expression \( 8^{0}+(0.50)^{-3}-(0.25)^{-2}-3^{2} \). First, according to the rules of exponents, any non-zero number raised to the power of zero equals 1, so \( 8^{0} = 1 \). Next, for \( (0.50)^{-3} \), the negative exponent indicates a reciprocal. Therefore, \( (0.50)^{-3} = \frac{1}{(0.50)^{3}} = \frac{1}{0.125} = 8 \). Now for \( (0.25)^{-2} \), again applying the rule for negative exponents gives us \( (0.25)^{-2} = \frac{1}{(0.25)^{2}} = \frac{1}{0.0625} = 16 \). Finally, evaluating \( 3^{2} \) results in \( 9 \). Putting all this together, we compute: \[ 1 + 8 - 16 - 9 = 1 + 8 - 16 - 9 = -16 \] Thus, the final result is \( -16 \).