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To solve the equation \( \frac{1}{2 x}=\frac{1}{x+1} \), you can cross-multiply to eliminate the fractions. This gives you \( (x + 1) = 2x \). Rearranging the equation results in \( x + 1 - 2x = 0 \), or simplified, \(-x + 1 = 0\). Therefore, \( x = 1 \) is the solution! However, let's check for any restrictions. Since the original equation has terms involving \( x \) in the denominator, \( x \) cannot be equal to 0 (to avoid division by zero). The solution \( x = 1 \) is valid since it doesn't fall under that restriction!
