5 Which does NOT show a correct comparison of two fractions? $$ \begin{array}{ll} ext { A } \frac{5}{15}=\frac{2}{5} & ext { C } \frac{3}{9}=\frac{1}{3} \ ext { B } \frac{3}{7}=\frac{6}{14} & ext { D } \frac{4}{10}=\frac{2}{5}\end{array} $$

Question

5 Which does NOT show a correct comparison of two fractions? $$ \begin{array}{ll}	ext { A } \frac{5}{15}=\frac{2}{5} & 	ext { C } \frac{3}{9}=\frac{1}{3} \ 	ext { B } \frac{3}{7}=\frac{6}{14} & 	ext { D } \frac{4}{10}=\frac{2}{5}\end{array} $$

UpStudy AI · Accepted Answer

**Step 1:** Examine Option A  
We have  
$$
\frac{5}{15} \quad \text{and} \quad \frac{2}{5}
$$  
Simplify $$\frac{5}{15}$$ by dividing numerator and denominator by 5:  
$$
\frac{5}{15} = \frac{1}{3}
$$  
Since  
$$
\frac{1}{3} \neq \frac{2}{5},
$$  
Option A is not a correct comparison.

**Step 2:** Examine Option B  
We have  
$$
\frac{3}{7} \quad \text{and} \quad \frac{6}{14}
$$  
Multiply the numerator and the denominator of $$\frac{3}{7}$$ by 2:  
$$
\frac{3 \times 2}{7 \times 2} = \frac{6}{14}
$$  
Thus, $$\frac{3}{7} = \frac{6}{14}$$.

**Step 3:** Examine Option C  
We have  
$$
\frac{3}{9} \quad \text{and} \quad \frac{1}{3}
$$  
Simplify $$\frac{3}{9}$$ by dividing numerator and denominator by 3:  
$$
\frac{3}{9} = \frac{1}{3}
$$  
Thus, $$\frac{3}{9} = \frac{1}{3}$$.

**Step 4:** Examine Option D  
We have  
$$
\frac{4}{10} \quad \text{and} \quad \frac{2}{5}
$$  
Simplify $$\frac{4}{10}$$ by dividing numerator and denominator by 2:  
$$
\frac{4}{10} = \frac{2}{5}
$$  
Thus, $$\frac{4}{10} = \frac{2}{5}$$.

**Conclusion:**  
Option A does not show a correct comparison of the two fractions.
Option A does not correctly compare the fractions.

5 Which does NOT show a correct comparison of two fractions? \( \begin{array}{ll}\text { A } \frac{5}{15}=\frac{2}{5} & \text { C } \frac{3}{9}=\frac{1}{3} \\ \text { B } \frac{3}{7}=\frac{6}{14} & \text { D } \frac{4}{10}=\frac{2}{5}\end{array} \)

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