Given the function \[ \begin{array}{l} f(x)=\left\{\begin{array}{ll}9 x-4 & x<0 \\ 9 x-8 & x \geq 0\end{array}\right. \\ \text { Calculate the following values: } \\ f(-1)=\square \\ f(0)=\square \\ f(2)=\square\end{array} \]

To calculate the values of the function \( f(x) \): 1. For \( f(-1) \): Since \( -1 < 0 \), we use the first piece of the function: \[ f(-1) = 9(-1) - 4 = -9 - 4 = -13 \] So, \( f(-1) = -13 \). 2. For \( f(0) \): Since \( 0 \geq 0 \), we use the second piece of the function: \[ f(0) = 9(0) - 8 = 0 - 8 = -8 \] So, \( f(0) = -8 \). 3. For \( f(2) \): Since \( 2 \geq 0 \), we again use the second piece of the function: \[ f(2) = 9(2) - 8 = 18 - 8 = 10 \] So, \( f(2) = 10 \). Putting it all together, we have: - \( f(-1) = -13 \) - \( f(0) = -8 \) - \( f(2) = 10 \) Thus, the final answers are: \[ f(-1) = -13 \] \[ f(0) = -8 \] \[ f(2) = 10 \]