Insert the two whole numbers on both sides of \( v \) \( \square<\sqrt{24}<\square \)

We need to find two whole numbers such that \[ \square < \sqrt{24} < \square. \] **Step 1.** Find two consecutive whole numbers \(a\) and \(a+1\) such that \[ a^2 < 24 < (a+1)^2. \] **Step 2.** Test \(a = 4\): \[ 4^2 = 16 \quad \text{and} \quad 5^2 = 25. \] Since \[ 16 < 24 < 25, \] it follows that \[ 4 < \sqrt{24} < 5. \] Thus, the two whole numbers are \(4\) and \(5\).