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Bonus Knowledge
To solve \( \sqrt[3]{8 m^{6} n^{12} p^{21} q^{3}} \), we can simplify each component inside the cube root. First, break it down: \( \sqrt[3]{8} = 2 \), because \( 2^3 = 8 \). For the variables: - \( \sqrt[3]{m^{6}} = m^{2} \) (since \( 6 \div 3 = 2 \)) - \( \sqrt[3]{n^{12}} = n^{4} \) (since \( 12 \div 3 = 4 \)) - \( \sqrt[3]{p^{21}} = p^{7} \) (since \( 21 \div 3 = 7 \)) - \( \sqrt[3]{q^{3}} = q^{1} \) (since \( 3 \div 3 = 1 \)) Now combine these results: \[ \sqrt[3]{8 m^{6} n^{12} p^{21} q^{3}} = 2 m^{2} n^{4} p^{7} q \] So the final expression is \( 2 m^{2} n^{4} p^{7} q \).
