According to the U.S. Census Bureau, the probability that a randomly selected worker primarily drives a car to work is 0.7637 . The probability that a randomly selected worker primarily takes public transportation to work is 0.0509 . Complete parts (a) through (d). (a) What is the probability that a randomly selected worker primarily drives a car or takes public transportation to work? P (worker drives a car or takes public transportation to work) \( = \) (Round to four decimal places as needed.)

To find the probability that a randomly selected worker either drives a car or takes public transportation, we can use the formula for the union of two events. Here, we have: - \(P(A) = 0.7637\) (probability that a worker drives a car) - \(P(B) = 0.0509\) (probability that a worker takes public transportation) Since these two events are mutually exclusive (a worker cannot do both at the same time), we add their probabilities: \[P(A \cup B) = P(A) + P(B) = 0.7637 + 0.0509 = 0.8146\] Thus, the probability that a randomly selected worker primarily drives a car or takes public transportation to work is **P (worker drives a car or takes public transportation to work) = 0.8146.**