\( 7 x^{2} \div 3 x-2=0 \) leave your answer cors

Solve the equation \( 7x^{2} \div (3x-2)=0 \). Solve the equation by following steps: - step0: Solve for \(x\): \(7x^{2}\div \left(3x-2\right)=0\) - step1: Find the domain: \(7x^{2}\div \left(3x-2\right)=0,x\neq \frac{2}{3}\) - step2: Rewrite the expression: \(\frac{7x^{2}}{3x-2}=0\) - step3: Cross multiply: \(7x^{2}=\left(3x-2\right)\times 0\) - step4: Simplify the equation: \(7x^{2}=0\) - step5: Rewrite the expression: \(x^{2}=0\) - step6: Set the base equal to 0: \(x=0\) - step7: Check if the solution is in the defined range: \(x=0,x\neq \frac{2}{3}\) - step8: Find the intersection: \(x=0\) The solution to the equation \(7x^{2} \div (3x-2) = 0\) is \(x = 0\).