Pregunta
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10. The number of students in mathematies class is four fifths the number of students in English class, The total number of students in both classes doesn't exceed 54 . What is the greatest possible number of students in the English class?

Ask by Dawson Whittaker. in Ethiopia
Mar 10,2025

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The greatest possible number of students in the English class is 30.

Solución

Let \( E \) be the number of students in the English class and \( M \) be the number of students in the mathematics class. According to the problem, we have: 1. \( M = \frac{4}{5}E \). 2. The total number of students does not exceed 54: \[ E + M \leq 54. \] Substitute \( M \) into the total: \[ E + \frac{4}{5}E \leq 54. \] Combine like terms: \[ \frac{9}{5}E \leq 54. \] Multiply both sides by \(\frac{5}{9}\) to solve for \( E \): \[ E \leq 54 \times \frac{5}{9} = 30. \] Since the number of students must be an integer and \( M = \frac{4}{5}E \) must also be an integer, \( E \) must be a multiple of 5. The greatest multiple of 5 that does not exceed 30 is \( 30 \) itself. Thus, the greatest possible number of students in the English class is \( 30 \).

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Let the number of students in the English class be \( E \) and the number of students in the Mathematics class be \( M \). According to the problem, \( M = \frac{4}{5}E \). The total students in both classes is given by the equation: \[ M + E \leq 54 \] Substituting for \( M \), we get: \[ \frac{4}{5}E + E \leq 54 \] Combining the terms: \[ \frac{9}{5}E \leq 54 \] Multiplying both sides by \( \frac{5}{9} \): \[ E \leq 30 \] Therefore, the greatest possible number of students in the English class is **30**. Now, to find the number of students in the Mathematics class, we substitute back: \[ M = \frac{4}{5} \times 30 = 24 \] So, we have 30 students in the English class and 24 in the Mathematics class, which adds up to 54 in total—just at the limit!

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