Pregunta
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The graph of
is a parabola opening upward with its vertex at
. It crosses the
-axis at
and
, and the
-axis at
.
Solución
Step 1. Write the Equation and Identify Coefficients:
The quadratic function is given by
The quadratic function is given by
This is in the standard form
where
Step 2. Determine the Vertex:
The vertex of a parabola in standard form has -coordinate
The vertex of a parabola in standard form has
Substitute the coefficients:
Then, substitute
into the equation to find the
-coordinate:
Thus, the vertex is at
Step 3. Identify the Axis of Symmetry:
The axis of symmetry is the vertical line passing through the vertex. Its equation is
The axis of symmetry is the vertical line passing through the vertex. Its equation is
Step 4. Find the
-Intercepts:
Set and solve for
:
Set
Rearrange the equation:
Taking the square root of both sides yields:
Thus, the
-intercepts are
Step 5. Find the
-Intercept:
Set in the equation:
Set
So the
-intercept is at
Step 6. Describe the Graph:
- The parabola opens upward since
. - The vertex is the lowest point, at
. - The graph is symmetric about the line
. - It crosses the
-axis at and , and the -axis at .
Respondido por UpStudy AI y revisado por un tutor profesional
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Beyond the Answer
Did you know that the equation
represents a parabola? This particular parabola opens upwards, and its vertex is located at the point (0, -1). Parabolas like this one are not just abstract concepts; they can be seen in real-life structures such as bridges and satellite dishes, where the shape helps in distributing weight and focusing signals efficiently!
When working with this equation, a common mistake is forgetting to plot the vertex and the axis of symmetry. The vertex is crucial because it indicates the minimum point for curves that open upwards. Always remember to check the y-intercept (when
,
) and other key points to sketch the graph accurately!

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