5. Reilly used \( 1 \frac{7}{10} \) tubes of paint to paint a model. He used \( 2 \frac{3}{8} \) tubes finish an art project. How many tubes did he use in total?

To find the total number of tubes of paint Reilly used, we simply need to add the two amounts together: \( 1 \frac{7}{10} + 2 \frac{3}{8} \). First, convert the mixed numbers into improper fractions: - \( 1 \frac{7}{10} = \frac{10 \cdot 1 + 7}{10} = \frac{17}{10} \) - \( 2 \frac{3}{8} = \frac{8 \cdot 2 + 3}{8} = \frac{19}{8} \) Next, find a common denominator to add these fractions. The least common multiple of 10 and 8 is 40. Convert both fractions: - \( \frac{17}{10} = \frac{17 \cdot 4}{10 \cdot 4} = \frac{68}{40} \) - \( \frac{19}{8} = \frac{19 \cdot 5}{8 \cdot 5} = \frac{95}{40} \) Now, add the two fractions: \[ \frac{68}{40} + \frac{95}{40} = \frac{163}{40} \] Finally, convert \( \frac{163}{40} \) back to a mixed number: \( 163 \div 40 = 4\) with a remainder of 3. So, \[ \frac{163}{40} = 4 \frac{3}{40} \] Thus, Reilly used a total of \( 4 \frac{3}{40} \) tubes of paint.