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Multiply. \( 8 a b\left(x a^{8}+y a+3\right) \)

Ask by Santiago Carter. in the United States
Mar 09,2025

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\( 8xa^9b + 8ya^2b + 24ab \)

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To multiply \( 8 a b\left(x a^{8}+y a+3\right) \), distribute \( 8 a b \) to each term inside the parentheses. This gives: 1. \( 8 a b \cdot x a^{8} = 8 a^{2} b x a^{8} = 8 a^{9} b x \) 2. \( 8 a b \cdot y a = 8 a^{2} b y \) 3. \( 8 a b \cdot 3 = 24 a b \) Putting it all together, the final result is: \[ 8 a^{9} b x + 8 a^{2} b y + 24 a b \]

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