Find the domain and intercepts. \( f(x)=\frac{90}{x-5} \) Find the domain. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The domain is all real \( x \), except \( x=\square \). B. The domain is all real numbers.
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The domain of the function \( f(x)=\frac{90}{x-5} \) consists of all real numbers except where the denominator equals zero. To find that point, set \( x-5=0 \), leading to \( x=5 \). Therefore, the domain is all real \( x \), except \( x=5 \). For the intercepts, to find the y-intercept, set \( x=0 \), giving \( f(0)=\frac{90}{0-5}=-18 \). To find the x-intercept, set \( f(x)=0 \), but since the numerator is constant (90), there is no x-intercept. So we have a y-intercept at (0, -18) and no x-intercept!
