F)) Factor completely. \( 3 s^{2}+8 s-3 \) Submit
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Beyond the Answer
To factor the quadratic expression \(3s^2 + 8s - 3\), you can look for two numbers that multiply to the product of the coefficient of \(s^2\) (which is \(3\)) and the constant term (which is \(-3\)), giving you \(-9\) (i.e., \(3 \times -3\)), while also adding up to the middle coefficient, which is \(8\). These two numbers are \(9\) and \(-1\). So, you rewrite the expression as: \(3s^2 + 9s - s - 3\) Now, group the terms: \((3s^2 + 9s) + (-s - 3)\) Factoring out the common factors gives you: \(3s(s + 3) - 1(s + 3)\) Therefore, you can factor it completely as: \((3s - 1)(s + 3)\). Happy factoring!
