Solve the system by the elimination/addition method \( -3 x-4 y=-13 \) \( -1 x+5 y=2 \)

Solve the system of equations \( -3x-4y=-13;-x+5y=2 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}-3x-4y=-13\\-x+5y=2\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}-3x-4y=-13\\x=-2+5y\end{array}\right.\) - step2: Substitute the value of \(x:\) \(-3\left(-2+5y\right)-4y=-13\) - step3: Simplify: \(6-19y=-13\) - step4: Move the constant to the right side: \(-19y=-13-6\) - step5: Subtract the numbers: \(-19y=-19\) - step6: Change the signs: \(19y=19\) - step7: Divide both sides: \(\frac{19y}{19}=\frac{19}{19}\) - step8: Divide the numbers: \(y=1\) - step9: Substitute the value of \(y:\) \(x=-2+5\times 1\) - step10: Substitute back: \(x=-2+5\) - step11: Calculate: \(x=3\) - step12: Calculate: \(\left\{ \begin{array}{l}x=3\\y=1\end{array}\right.\) - step13: Check the solution: \(\left\{ \begin{array}{l}x=3\\y=1\end{array}\right.\) - step14: Rewrite: \(\left(x,y\right) = \left(3,1\right)\) The solution to the system of equations by the elimination/addition method is \( (x,y) = (3,1) \).