What is the product? \( 6\left(x^{2}-1\right) \cdot \frac{6 x-1}{6(x+1)} \)
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To simplify the expression \( 6\left(x^{2}-1\right) \cdot \frac{6 x-1}{6(x+1)} \), we start by recognizing that \( x^2 - 1 \) can be factored. The factored form is \( (x-1)(x+1) \). Now, substituting that in, we have: \[ 6 \cdot (x-1)(x+1) \cdot \frac{6x-1}{6(x+1)} \] Notice that \( (x+1) \) in the numerator and denominator cancels out when \( x \neq -1\). Therefore, the product simplifies to: \[ 6(x-1) \cdot \frac{6x-1}{6} \] The \( 6 \) in the numerator and denominator cancels, giving: \[ (x-1)(6x-1) \] Now, distributing this product results in: \[ 6x^2 - x - 6 + 1 \] Combining terms yields: \[ 6x^2 - 7x + 1 \] Thus, the simplified product is: \[ 6x^2 - 7x + 1 \]
